On this blog you can find the complete X-Test solutions: here is Part 4. Part 4 is the last and the hardest part of the whole test, the part which I designed thinking to IQs above 150 SD 15. Item 15 was designed by me thinking to IQs above 170 SD 15 and it remains one of the three unsolved items in the whole test (together with items 5 and 6 of part 3).
OLD VERSION
PART 4:
OLD VERSION
PART 4:
Numerical sequences (the X represent hidden elements
and/or elements that are impossible to explicitate):
1) q1w2e3?4t5??
(q1w2e3r4t5y6 - QWERTY and QWERTZ (q1w2e3r4t5z6) are both correct RAW score 1/1)
2) 567891234, 68954123, 89563412, ? (956824341)
3) -3,X,0,X,3,333,6,66663,9,?,?,.. (999999999,12)
4) SOC0, V2, ILT5, MNFH14, WEI? (WEI9 - in fact, A=N=3, C=O=0, etc... you have to cosider the original font I used in the original .docx/PDF you can find on Box.net)
5) 5,5,1,6,0,2,4,?,1,3,7,-2,0,?,4,?,-3,-1
,… (5,5,1,6,0,2,4,-1,1,3,7,-2,0,2,4,3,-3,-1 - see item 8)
6) i,0,1,? (i,0,1,1.4142… - sqrt(-1), sqrt(0), sqrt(1)--> sqrt(2))
7) You know that
26=(5*5)+1: EIMQU,CGKTX,?, EIMQU
(AJNRWZ - you have to draw a (5x5)+1 square grid of letters)
8) 10,10,1,11,0,2,4,X,?,?,?,... (10, 10, 1, 11, 0, 2, 4, X, 1, 3, 12,... - This item is connected with item 5)... IMHO it is a common flaw belonging to most of widely accepted HRTs!!)
9) Y*Y=Z
Z-1=1111 ; find the value of y, the solution isn’t sqrt(1110) (y=sqrt(16)=4=100)
10) 0,0,4142,7320,0,2360,4494,?
(the solution is 6457)
(you have to look at the decimal parts of sqrt(1), sqrt(2), sqrt(3), sqrt(4), etc...)
11) 2,5,7,23,?,53,73,.. (? = 37)
12) ?,17,24,38,59,94,153,?,?,… (?,?,? = 1,..,377,993 - base 17, why not?)
13) You know that e=2,718281828459045235360287471352.. and pi=3,141592653589793238462643383279..;
complete the logical sequences:
a - 101011101011X110???... (X,X,1)
b - XXX234536???... (4,7,8) [comparison between "e" and "pi"]
14) ?,F,O,N,C,B;10,9,8,7,6,5 (Ne - periodic table of the elements, do you know?)
15) UNSOVED ITEM) You have to translate the word GONIOMETRIC in a strange alphabet
related to “the area of a circle with unitary range”, you know that the world
CIRCLE is represented by LQXUE: how you will write GONIOMETRIC? (PWTRMIUUH)
Cicle-->pi (3.14159265358979328...) Area-->pi^2 (9.869604401089358)
(PWTRMIUUH) (Option 2: PWTRMIUF--> 0,5 points out of 1)
NEW VERSION
PART 4:
1) You are in a decimal system. You can use only two integer numbers – from 0 to 9 - (different from each other) and relate them using only two of the following operators (you can’t use the same operator twice): What is the greatest number you can obtain? You can also insert the “( )” to choose the order of the operations.
NEW VERSION
PART 4:
Numerical sequences (the X represent hidden elements
and/or elements that are impossible to explicitate):
1) You are in a decimal system. You can use only two integer numbers – from 0 to 9 - (different from each other) and relate them using only two of the following operators (you can’t use the same operator twice): What is the greatest number you can obtain? You can also insert the “( )” to choose the order of the operations.
( (8^9)! )
2) 567891234, 68954123, 89563412, ? (956824341)
3) -3,X,0,X,3,333,6,66663,9,?,?,.. (999999999,12)
4) SOC0, V2, ILT5, MNFH14, WEI? (WEI9 - in fact, A=N=3, C=O=0, etc... you have to cosider the original font I used in the original .docx/PDF you can find on Box.net)
5) 5,5,1,6,0,2,4,?,1,3,7,-2,0,?,4,?,-3,-1
,… (5,5,1,6,0,2,4,-1,1,3,7,-2,0,2,4,3,-3,-1 - see item 8)
6) i,0,1,? (i,0,1,1.4142… - sqrt(-1), sqrt(0), sqrt(1)--> sqrt(2))
7) You know that
26=(5*5)+1: EIMQU,CGKTX,?, EIMQU
(AJNRWZ - you have to draw a (5x5)+1 square grid of letters)
8) 10,10,1,11,0,2,4,X,?,?,?,... (10, 10, 1, 11, 0, 2, 4, X, 1, 3, 12,... - This item is connected with item 5)... IMHO it is a common flaw belonging to most of widely accepted HRTs!!)
9) Y*Y=Z
Z-1=1111 ; find the value of y, the solution isn’t sqrt(1110) (y=sqrt(16)=4=100)
10) 0,0,4142,7320,0,2360,4494,?
(the solution is 6457)
(you have to look at the decimal parts of sqrt(1), sqrt(2), sqrt(3), sqrt(4), etc...)
11) 2,5,7,23,?,53,73,..
(The solution is: 3; L; P, 6 - you can draw it on the .jpg figure, obviously)
12) ?,17,24,38,59,94,153,?,?,… (?,?,? = 1,..,377,993 - base 17, why not?)
13) You know that e=2,718281828459045235360287471352.. and pi=3,141592653589793238462643383279..;
complete the logical sequences:
a - 101011101011X110???... (X,X,1)
b - XXX234536???... (4,7,8) [comparison between "e" and "pi"]
14)
b- C, T, S, P, ? ; ?, 3, 4, 5, X (H, 1 - same thing as above: Circle, Triangle, Square,...)
a-
?,F,O,N,C,B;10,9,8,7,6,5 (Ne - periodic table of the elements, do you know?)
b- C, T, S, P, ? ; ?, 3, 4, 5, X (H, 1 - same thing as above: Circle, Triangle, Square,...)
15) UNSOVED ITEM) You have to translate the word GONIOMETRIC in a strange alphabet
related to “the area of a circle with unitary range”, you know that the world
CIRCLE is represented by LQXUE: how you will write GONIOMETRIC? (PWTRMIUUH)
Cicle-->pi (3.14159265358979328...) Area-->pi^2 (9.869604401089358)
(PWTRMIUUH) (Option 2: PWTRMIUF--> 0,5 points out of 1)
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